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	<title>Comments on: Unplanned planning</title>
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	<link>http://lbrandy.com/blog/2009/12/unplanned-planning/</link>
	<description>{ on programming and the internets, every monday }</description>
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		<title>By: greggT</title>
		<link>http://lbrandy.com/blog/2009/12/unplanned-planning/comment-page-1/#comment-26163</link>
		<dc:creator>greggT</dc:creator>
		<pubDate>Wed, 30 Dec 2009 02:21:46 +0000</pubDate>
		<guid isPermaLink="false">http://lbrandy.com/blog/?p=1176#comment-26163</guid>
		<description>In medical imaging, we talk a point in either of 2 interpretations: a single point or a 1x1 area whose average is represented at a single location.

The former requires that you specify where in the square that measurement is taken.  It can only be represented as a float, but you can, if you have rules, store them in int&#039;s such that the inverse operation is valid.

The latter is because medical images represent actual body tissues and usually average a measurement of these tissues (color, attenuation, opacity, etc) over an area (called an aperture), not at a single point.  Why? Because ALL measurements (not just in images) are taken over an area (or volume or time span or...).  Think of the aperture ring on a camera -- does it have a zero setting? No. Even a pinhole camera has an aperture of the size of a pin, which is NOT zero.  A zero sized aperture is not a hole, and so nothing can pass thru it.

So you cannot make a rectangle of the latter concept, and must be careful about the former.</description>
		<content:encoded><![CDATA[<p>In medical imaging, we talk a point in either of 2 interpretations: a single point or a 1&#215;1 area whose average is represented at a single location.</p>
<p>The former requires that you specify where in the square that measurement is taken.  It can only be represented as a float, but you can, if you have rules, store them in int&#8217;s such that the inverse operation is valid.</p>
<p>The latter is because medical images represent actual body tissues and usually average a measurement of these tissues (color, attenuation, opacity, etc) over an area (called an aperture), not at a single point.  Why? Because ALL measurements (not just in images) are taken over an area (or volume or time span or&#8230;).  Think of the aperture ring on a camera &#8212; does it have a zero setting? No. Even a pinhole camera has an aperture of the size of a pin, which is NOT zero.  A zero sized aperture is not a hole, and so nothing can pass thru it.</p>
<p>So you cannot make a rectangle of the latter concept, and must be careful about the former.</p>
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		<title>By: Michael</title>
		<link>http://lbrandy.com/blog/2009/12/unplanned-planning/comment-page-1/#comment-26074</link>
		<dc:creator>Michael</dc:creator>
		<pubDate>Sat, 12 Dec 2009 16:41:57 +0000</pubDate>
		<guid isPermaLink="false">http://lbrandy.com/blog/?p=1176#comment-26074</guid>
		<description>Anonymous has it right--just use x/y and height/width.</description>
		<content:encoded><![CDATA[<p>Anonymous has it right&#8211;just use x/y and height/width.</p>
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		<title>By: Les</title>
		<link>http://lbrandy.com/blog/2009/12/unplanned-planning/comment-page-1/#comment-26044</link>
		<dc:creator>Les</dc:creator>
		<pubDate>Tue, 08 Dec 2009 12:30:35 +0000</pubDate>
		<guid isPermaLink="false">http://lbrandy.com/blog/?p=1176#comment-26044</guid>
		<description>I thought the lower right corner would be x=10,y=0.

And the number of points in the image is determined by how your language declares an array[10,10].  Zero based? Is the 10 inclusive or not?</description>
		<content:encoded><![CDATA[<p>I thought the lower right corner would be x=10,y=0.</p>
<p>And the number of points in the image is determined by how your language declares an array[10,10].  Zero based? Is the 10 inclusive or not?</p>
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		<title>By: Trevor</title>
		<link>http://lbrandy.com/blog/2009/12/unplanned-planning/comment-page-1/#comment-26041</link>
		<dc:creator>Trevor</dc:creator>
		<pubDate>Tue, 08 Dec 2009 03:55:24 +0000</pubDate>
		<guid isPermaLink="false">http://lbrandy.com/blog/?p=1176#comment-26041</guid>
		<description>&quot;Hopefully, your answers disagreed (or at least you can see how they could disagree).&quot;

I don&#039;t see how they can disagree.</description>
		<content:encoded><![CDATA[<p>&#8220;Hopefully, your answers disagreed (or at least you can see how they could disagree).&#8221;</p>
<p>I don&#8217;t see how they can disagree.</p>
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		<title>By: Anonymous</title>
		<link>http://lbrandy.com/blog/2009/12/unplanned-planning/comment-page-1/#comment-26038</link>
		<dc:creator>Anonymous</dc:creator>
		<pubDate>Mon, 07 Dec 2009 19:34:34 +0000</pubDate>
		<guid isPermaLink="false">http://lbrandy.com/blog/?p=1176#comment-26038</guid>
		<description>And this is why I use struct rect { float left, top, width, height; }   :)</description>
		<content:encoded><![CDATA[<p>And this is why I use struct rect { float left, top, width, height; }   <img src='http://lbrandy.com/blog/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
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